Use the Quadratic Formula to solve

x²-13x+42=0

x1=7,

x2=6

Step-by-step explanation:

x²-13x+42=0

a=1, b=-13, c=42

x1,2=(-b+-sqrt(b^2-4ac)) /2a

x1,2=(-(-13)+-sqrt((-13)^2-4*1*42))/2*1

x1,2=(13+-sqrt (169-168))/2

x1,2=(13+-sqrt(1))/2

x1,2=(13+-1)/2

x1=(13+1)/2, x2=(13-1)/2

x1=14/2, x2=12/2

x1=7, x2 =6

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

i need points

step-by-step explanation: