F(−2)=3 f′(−2)=4 g(4)=5 g′(4)=2

The point (−2,4) lies on the curve in the xy -plane given by the equation f(x)g(y)=17−x−y , where f is a differentiable function of x and g is a differentiable function of y . Selected values of f , f′ , g , and g′ are given in the table above. What is the value of dydx at the point (−2,4) ?

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.

don't give

take it once

try and try and you will not

happy to

pls mark as brainliest

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°

98%

step-by-step explanation: