I need help please. Thanks

Given:

m∠APD = (7x + 1)°

m∠DPC = 90°

m∠CPB = (9x - 7)°

To find:

The measure of arc ACD.

Solution:

Sum of the adjacent angles in a straight line = 180°

m∠APD + m∠DPC + m∠CPB = 180°

7x° + 1° + 90° + 9x° - 7° = 180°

16x° + 84° = 180°

Subtract 84° from both sides.

16x° + 84° - 84° = 180° - 84°

16x° = 96°

Divide by 16° on both sides.

x = 6

m∠APB = 180°

m∠BPD = (9x - 7)° + 90°

             = (9(6) - 7)° + 90°

             = 47° + 90°

m∠BPD = 137°

m∠APD = m∠APB + m∠BPD

             = 180° + 137°

             = 317°

The measure of the central angle is congruent to the measure of the intercepted arc.

m(ar ACD) = m∠APD

m(ar ACD) = 317°

The arc measure of ACD is 317°.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: c. is your answer

step-by-step explanation: get me a black leather coat