Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Find v when a is 4 m/s squared, u is 3 m/s, and t is 72 seconds

v= 291 m/s squared

Step-by-step explanation:

v= ?

a=4 m/s squared

u=3 m/s

t=72 secs

v=u+a(t)

v=3 m/s +4 m/s (72 secs)

v=3 m/s + 288 m/s

v= 291 m/s squared

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)