What are the x-intercepts of the graph of y = -x2 - 6x + 40?

x=-10                    x=4

Step-by-step explanation:

y = -x^2 - 6x + 40

To find the x intercepts set y =0 and solve for x

0 = -x^2 - 6x + 40

Divide by -1

0 =  x^2 + 6x - 40

What two numbers multiply to -40 and add to 6

10*-4 = -40

10 -4 = 6

(x+10) (x-4) =0

Using the zero product property

x+10 =0          x-4=0

x+10-10=0-10    x-4+4=0+4

x=-10                    x=4

1.3 million hoops i believe