A softball coach needs to choose 9 players to be in the batting lineup for the next game. There are 4 freshmen, 5 sophomores, 6 juniors, and 5 seniors on the team. Step 1 of 2 : How many ways can the batting order be chosen if the coach wants no more than 2 freshmen to be in the lineup

The batting order can be chosen in 6,572,966,400 ways.

Step-by-step explanation:

The order in which the players are in the lineup is important. That is, if we exchange two players positions in the batting order, we have an entire new batting order. So the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

No more than 2 freshmen

Either no freshmen, 1 freshmen or two freshman.

No freshmen:

9 players from a set of 16(sophmores, juniors and seniors).

1 freshmen:

One freshmen, from a set of 4.

8 non-freshmen, from a set of 16. So

2 freshmen:

2 freshmen, from a set of 4.

7 non-freshmen, from a set of 16.

Total:

The batting order can be chosen in 6,572,966,400 ways.

there are no figures how am i supposed to answer this question

step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it