What is the center and radius of a circle with the equation x^2+y^2+4y+4=36
Idk how to get it to the standard equation of a circle. Thanks in advance

Step-by-step explanation:

You have to complete the square in order to find the center and the radius of this.  Let's begin by putting it in sort-of standard form.  I'm going to move thee 4 over to the other side by the 36:

You should be able to tell right away, if you are at this point in your learning about circles, that the h coordinate of the center is 0.  There is no linear term for the x, only a squared term.  The linear term is the one that dictates the side to side movement.  If there is no linear, or x-term, the circle does not move from x = 0.  But there is a linear term on the y.  It is 4y.  So while we cannot complete the square on the x term, we can on the y.  The rule is to take half the linear term, square it, and add that squared value in to both sides.  Our linear y term is 4.  Half of 4 is 2, and 2 squared is 4.  So we add 4 to both sides:

The reason you complete the square is to get to the perfect square binomial which will tell you what the center is.  I will state the binomial on the left along with simplifying on the right:

That''s the standard form of that circle.  The center is (0, -2) and the radius is the square root of 36 which is 6.

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system