Evaluating Quadratic Functions Find the indicated function values.

f(–4) =
f(0) =
f(1) =

f(-4) = 6

f(0) = -6

f(1) = -4

On a coordinate plane, a parabola opens up. It goes through (negative 4.25, 10), has a vertex of (negative 0.5, negative 6.2), and goes through (3.25, 10). Solid circles appear on the parabola at (negative 4, 6), (negative 2, negative 4), (negative 1, negative 6), (0, negative 8), (1, negative 4), (2, 0), and (3, 6).

Step-by-step explanation:

hope it helps

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

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