β6y
Mathematics, 02.04.2020 03:28, drodriguez2324
Takumi and Kaliska manipulated the rational expression \dfrac{-9y^2 - 3y}{-6y^2 - 6y}
β6y
2
β6y
β9y
2
β3y
start fraction, minus, 9, y, squared, minus, 3, y, divided by, minus, 6, y, squared, minus, 6, y, end fraction. Their responses are shown below.
Takumi Kaliska
\dfrac{-3y(3y+1)}{-6y(y+1)}
β6y(y+1)
β3y(3y+1)
start fraction, minus, 3, y, left parenthesis, 3, y, plus, 1, right parenthesis, divided by, minus, 6, y, left parenthesis, y, plus, 1, right parenthesis, end fraction \dfrac{3y+1}{2y+2}
2y+2
3y+1
start fraction, 3, y, plus, 1, divided by, 2, y, plus, 2, end fraction
Answers: 2
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Answers: 1
Takumi and Kaliska manipulated the rational expression \dfrac{-9y^2 - 3y}{-6y^2 - 6y}
β6y
β6y
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