Un avión que vuela a 1 kilómetro de altura debe aterrizar en el inicio de una pista de aterrizaje que se encuentra exactamente a 2 kilómetros de la punta del avión. Si dicho avión empieza a aterrorizar en ese momento, ¿cuál será su ángulo?

30°

Step-by-step explanation:

If we assume a right triangle, where the height is the opposite leg to the angle we are looking for and the distance from the beginning of an airstrip to the tip of the plane is the hypotenuse, we have to:

Sin ° A = Opposite leg / hypotenuse

Sin ° A = 1/2

° A = Arc Sin (1/2)

° A = 30 °

Which means that the angle that is formed is 30 °

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

step-by-step explanation: