What is the slope of a line that includes the points (–4, 1) and (10, –6)?

-

Step-by-step explanation:

The slope of a given point;

m=y₂-y₁/x₂-x₁

From question;

(-4,1) = (x₁, y₁)

(10,-6)= (X₂, y₂)

Where y₂ = -6, y₁= 1, x₂= 10, x₁=-4

Therefore;

m=

m=

m=

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)