Lou and Jacob each sold 200 pieces of jewelry. If 20% of Lou’s sales were rings, and Jacob sold 35 rings, who sold more rings? How many more? Use the drop-down menus to explain your answer.

20% of 200 is 40

lou sold the most rings

lou sold 5 more rings than jacob

Step-by-step explanation:

if 20% of 100 is 20 then you double it which gives you 40.

subtract 40 from 35, you get 5.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: