Mathematics, 01.04.2020 17:13, JAPONICA

A hemispherical tank is filled with water and has a diameter of 4 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?

Answers: 3

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Answers

The total weight of the water in a full tank, to the nearest pound is 1056 pounds, if water filled with water in the 4 diameter hemispherical tank and weighs 62.4 pounds per cubic foot.

Step-by-step explanation:

The given is,

A hemispherical tank is filled with water and has a diameter of 4 feet.

Water weighs 62.4 pounds per cubic foot

Step:1

Formula to weight of water is,

= Volume of water tank × weight of water per foot......(1)

Step:2

Formula to find volume of the tank is,

$V = \frac{2}{3} \pi r^{3}$ ...................................(2)

From given, r = Radius of Hemisphere

$r = \frac{d}{2}$

$= \frac{4}{2}$

r = 2 foot

From equation (2),

= $\frac{2}{3}$ × $\pi$ × $2^{3}$

= 16.755 cubic foot

Step:3

From equation (1),

= 16.775 × 62.4 (∵ Water weighs 62.4 pounds per cubic foot )

= 1045.52 pounds ( ∵ $foot^{3}$ × $\frac{pounds}{foot^{3}}$ = pounds )

≅ 1046 pounds

Weight of water in tank = 1046 pounds

Result:

The total weight of the water in a full tank, to the nearest pound is 1056 pounds, if a hemispherical tank is filled with water and it has 4 feet diameter and water weighs 62.4 pounds per cubic foot.

answered: Guest

arrange the equations with like terms in columns.

analyze the coefficients of x or y.

add the equations and solve for the remaining variable.

substitute the value into either equation and solve.

check the solution.

step-by-step explanation:

30 points easy question im just dumb me when solving this system of equations using linear combinat

answered: Guest

1/800 is the right answer

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A hemispherical tank is filled with water and has a diameter of 4 feet. If water weighs 62.4 pounds...