A dog is tied to a 30-foot leash that is tied to the corner of a building in the shape of a regular pentagon with a 10-foot sides. how much area does the dog have in which to play?

2735.25  ft squared

Step-by-step explanation:

If a dog is tied to a 30-foot leash that is tied to the corner of a building, we can image that the corner is the center of a circle that has a radius of 30-foot (same length with the leash).

So the area of the circle is:

Area = pi R² = 3.14* = 2826 ft squared

Sadly, he's not out in the middle of a field. He's tied to the corner  of the building so he can't cover the whole circle, because the building blocks a regular pentagon with a 10-foot sides.

We need to find out the area of the regular pentagon

A = 5 * where a is the base and b is the height.

with the property in a regular pentagon, we know that the height if it is:

b = tan(36) * = 3.63

=> area of the regular pentagon = 5* = 90.75 ft squared

=> area the dog have in which to play = area of the circle -  area of the regular pentagon =  2826 - 90.75 = 2735.25  ft squared

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.