What is the surface area of this design?
A.150in2
B.197in2
C.210in2
D.127in2

197 in ^2 (answer B of the list)

Step-by-step explanation:

Notice that this figure has a total of 6 faces, four of which are rectangles (whose area is calculated as "base times height") and two trapezoids (whose area is (B+b)H/2 ).

The total surface area is therefore the addition of these six areas:

Rectangles:

5 in x 5 in = 25 in^2

5 in x 5 in = 25 in^2

5 in x 6.4 in = 32 in^2

9 in x 5 in = 45 in^2

Trapezoids:

Two of equal dimensions: B = 9 in, b = 5 in, H = 5 in

2 * (9 in + 5 in) 5 in /2 = 70 in^2

Which gives a total of  (25 + 25 + 32+45 + 70) in^2 = 197 in^2

This agrees with answer B of he provided list.

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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