The diameter of a rod is 4 cm. If the material weighs 9.42 kg and has a
density of 6 g/cm3 . find the length of the rod. (Take π=3.14)

125

Step-by-step explanation:

R = 4 cm , r = 2 cm

weight = 9.42 kg --> 9420 g

density = 6 g/cm³

9420g/volume cm³ = 6 g/cm³

9420/6 = volume

1570 = volume

.

.

.

volume of a rod = 1570 cm³

πr²h = 1570

3.14×2×2×h = 1570

12.56×h = 1570

h = 125 cm

; length of the rod is 125 cm

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

what am i looking for finish the question.

step-by-step explanation: