Suppose the length of a catfish is normally distributed with a mean of 8.5 in and a standard deviation of 2 in. Which group describes 16% of the catfish population? Select each correct answer.
(Hint - there are 2 and there is a question like this one on the quiz)
(Select all that apply.)
Catfish that are shorter than 6.5in
Catfish that are between 6.5in and 8.5in
Catfish that are between 6.5in and 10.5in
Catfish that are longer than 10.5in

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

answer: it is d

step-by-step explanation:

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.