Andy has a snowball (a perfect sphere) with the radius of 3 cm. He wanted the snowball to be bigger, so he spent four seconds packing more snow onto it. Each second he spent packing, the snowballs radius increases by 0.25 cm. What is the ratio of the current volume of the snow bar to the original volume of the snowball.

237%

Step-by-step explanation:

Volume of original snowball:

.25 cm multiplied by 4 seconds equals 1 cm

3 cm + 1 cm = 4 cm

Volume of current snowball:

Ratio:

268.083/113.097= 2.37

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v