1. 100 units squared, each side is 10 units
2. a. 16 in squared b. 0.64 cm squared c. 0.0256 units squared. d.
3. a. 11cm b. 5/6 in c. 0.4 units d. x units
Step-by-step explanation:
okay this is long. . so for problem 1, you want to use the pythagorean theorem for 1 triangle you see, since all of them have the same side lengths. that would mean you use to find the missing side.
so, you know two sides are 8 and 6, so fill in the a and b: .
then simplify it. then . now you take the square root of both sides because you need c. which means . then, because the problem asks for the area of the square, you would do 10 times 10, which would give you the area as 100 (or 100 units squared). For the side lengths, you would say each side length is 10, but you would have to individually name each segment, I'm assuming.
for problem 2:
a: you would do 4 times 4 because the area is length times width. so, the area is 16 in squared.
b: you want to do 0.8 times 0.8 because that is the formula for area. this means the area is 0.64 cm squared.
c: you would do 0.16 times 0.16, which would give you 0.0256 units squared.
d: you would do t times t, which would give you because you do not know the value of t.
problem 3:
a: basically, because the area of a square is its side squared, the opposite of a squared is taking the square root. this means that you would take the square root of 121. , which equals 11, so the answer would be 11 cm.
b: you do the same thing as in a. . with fractions in a square root, you would actually write it like so: . then you would solve the roots individually, which would look like this in the end: 5/6, so the answer is 5/6 in.
c: you would take the square root of 0.16. , which is 0.4, so the answer is 0.4 units.
d: you would take the square root of , which would look like . to do square roots with variables, you would write it out.