White an expression for the pressure at a depth of d1 meters below the liquid surface

, where is the density of the liquid, and is the value of gravitational acceleration.

Step-by-step explanation:

Let be the density of a liquid. Let represent the gravitational acceleration (near the surface of the earth, .)

The pressure at a depth of under the surface of this liquid would be

.

Here's how to deduce this equation from the definition of pressure.

Pressure is the amount of force on a surface per unit area. For example, if a force of is applied over a surface with an area of , then the pressure on that surface would be (one Pascal.)

Consider a flat, square object that is horizontally submerged under some liquid at a depth of . Assume that is the area of that square. The volume of the liquid that sits on top of this square would be . If the density of that liquid is , then the mass of that much liquid would be .

The weight of that much liquid would be . The liquid on top of that object would exert a force of that size on the object. Since that force is exerted over an area of , the pressure on the object would be

.

In this question, . As a side note, if and are also in standard units ( for and for ), then would be in Pascals (, where .)

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step-by-step explanation: