Consider the function f(x) = 2sin(x2) on the interval 0 ≤ x ≤ 3.. (a) find the exact value in the given interval where an antiderivative, f, reaches its maximum.. x = . . (b) if f(1) = 9, estimate the maximum value attained by f. (round your answer to three decimal y ≈ .

So base in your question where there is a function f(x)=2sin(x^2) on a interval the following are the answer to your question on A and B.

A. X=pi/2 is the value of X in the given interval.
B. the possible value of x is 1 2 and 3 which gives the value of 0.034, 0.14, 0.313

i hope i answered your question

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