You randomly survey students about whether they are in favor of planting a community garden at school. Of 96 boys surveyed, 61 are in favor. Of 88 girls surveyed, 17 are against. Organize the results in a two-way table. What is the probability of randomly choosing a student that is against the garden and is a girl?
Please show all work I’m lost on this, thank you!

         boys           girls

yes    61               71

no     35               17

In order to find out how many boys are against you do 96 - 61. In order to find out how many girls are in favor you do 88 - 17.

In order to find the probability  you make a proportion. It will be:

So plug in you numbers.

Then you solve the proportion using cross multiplication.

So, the chance of randomly picking a girl that's against the garden is 9.23913043478%

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.