The children from a football club are put into rows in the sports hall
when put in rows of 9 children there are 2 children left over
when put into rows of 12 children there are 2 children left over
what is the least number of children in the football club

thanks ;0

Step-by-step explanation:

Let n be the number of children, n=6a+3 and n=8b+3, where a and b are numbers of rows. So 6a+3=8b+3, 6a=8b, 3a=4b, or a/b=4/3 so a=4 and b=3.  

Therefore n=27, the minimum number of children.

So the answer is 27.

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation:

all you have to do is multiply them both to see how many out comes you can put:

3 x 2 = 6

you can make 6 diferent combinations of crusts and toppings.

~batmans wife dun dun