Trig please help

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =13, c = 12, and m < A = 55*
How many distinct triangles can be drawn given these measurements?

One

Step-by-step explanation:

13/sin(55) = 12/sinC

sinC = 0.7561403486

C = 49.1, 130.9

Since 130.9+55 = 185.9 > 180

It will not form a triangle

So only one triangle possible with angle 49.1° at C

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length