Find the equation of the line that is perpendicular to the line x = −5 and passes through the point (1, 3.14).

A) y = 3.14
B) y = 3.14x
C) y =
1
5
x
D) y = −5x

A

Step-by-step explanation:

Perpendicular to x = -5 is going to be a horizontal line.

Since it passes through (1,3.14),

Equation is y = 3.14

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752