If an ace is worth 11 points and a 10 jack queen and king of worth 10 points each what is the probability that you will obtain 21 points with two carts

The correct answer is 0.048.

Step-by-step explanation:

A deck of card contains 52 cards of 4 different suits. This implies  there are 13 cards of each suits.

Each suit contains 1 ace and thus there are 4 aces in the deck. Each ace is of 11 points.

Each suit contains 4 cards of 10, jack, queen and king each having 10 points. This gives us that there are 16 cards with 10 points each.

We are drawing two cards without replacement.

Probability that we obtain 21 points with two cards will be if we get one 11 point card and the other 10 point card.

Thus the probability = × × 2! ( We are multiplying with 2! as we can either pick a 11 point card in the first instance or in the second instance).

Probability that one will obtain 21 points with two cards = = 0.048

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

the first option is the answer.