A university's administrator proposes to do an analysis of the proportion of graduates who have not found employment in their major field one year after graduation. In previous years, the percentage averaged 15%. He wants the margin of error to be within 5% at a 99% confidence level. What sample size will suffice? Round to the nearest integer.

339

Step-by-step explanation:

We have that the formula would come being:

n = p (1-p) * [z (α / 2) / B] ^ 2

let p, percentage averaged (0.15)

B = 5%, 0.05 (bottom margin)

α = 1 - A

A, top margin 99%

α = 1 - 0.99 = 0.01

α / 2 = 0.005

z (0.005) = 2.58 (attached normal distribution table), the value is negative in the table but is taken as positive.

Replacing we have:

n = 0.15 * (1 - 0.15) * [2.58 / 0.05] ^ 2

n = 0.1275 * (2.58 / 0.05) ^ 2

n = 339.4764

Therefore the sample size is 339.

the answer for this question is : 360°

step-by-step explanation:

we have been given a triangle   we need to tell which one of these is a triangle below to map onto itself.

360° rotation is the complete rotation which eventually leads to the same figure which is given.

the correct will be, that is 360° that will cause the triangle below to map onto itself.