What is the midpoint of EC?

The correct answer is first option

(t + p, r)

Step-by-step explanation:

Points to remember

midpoint formula

Length of a line segment with endpoints (x1, y1) and (x2, y2) is given by,

Midpoint= [(x2 + x1)/2 , (y2 + y1)/2]

To find the midpoint of EC

Let   (x1, y1) = E(2t, 0) and  (x2, y2) = C(2p, 2r)

Midpoint = [(2t + 2p)/2 , (0 + 2r)/2]

= (2(t + p)/2 , 2r/2)

= (t + p, r)

Therefore midpoint of EC = (t + p, r)

The correct answer is first option

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer