In 2003, the price of a certain automobile was approximately $32,000 with a depreciation of $1,740 per year. After how many years will the car's value be $23,300? a) Write an equation to model the problem. Let t represent the number of years after 2003. For example, the year 2005 would be represented by t = 2.

The correct answer is 5 years i.e. 2008.

Step-by-step explanation:

Price of the automobile in 2003 is $32000.

Depreciation per year is given by $1740.

Therefore let the car value is depreciated for t number of years.

Value depreciated for t years is given by $ (1740t).

The final value of the car after t years is given to be $23300.

Thus the equation is given by 32000 - 1740t = 23300.

⇒ 1740t = 32000 - 23300

⇒ 1740t = 8700

⇒ t = 5

Thus after 5 years the value of the car is $23300.

Thus in 2008 the depreciated price of the car would be $23300.

(2,20) means that the 2 is 2 hours and 20 is 20$. so there both 20$ for 2 hours only the same price. like it says. so, the dunk tank and the bounce house are the same price (20$) for the same amount of time (2 hours).

hope i

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,