The base of a solid is the region between the curve yequals3 cosine x and the x-axis from xequals0 to x equals StartFraction pi Over 2 EndFraction . The cross sections perpendicular to the x-axis are squares with bases running from the x-axis to the curve. Find a formula for the area A(x) of the cross sections of the solid perpendicular to the x-axis.

A=3(π/2)-1 au

Step-by-step explanation:

we have according to the graph that

f(x)=3

g(x)=cos(x)

Knowing A=∫|f(x)-g(x)|dx, then

; where a=0 and b=π/2

A=(3x-sin(x)) evaluated  0 ≤ x ≤ π/2

A=(3(π/2)-sin(π/2))-(3.0-sin(0))

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step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°