The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.02 ounces and a standard deviation of 0.15 ounce. Suppose that you draw a random sample of 28 cans. Find the probability that the mean weight of the sample is less than 6.01 ounces.

0.3605 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.02 ounces

Standard Deviation, σ = 0.15 ounce

Sample size, n = 28

We are given that the distribution of weight of can is a bell shaped distribution that is a normal distribution.

Formula:

Standard error due to sampling =

P(weight of the sample is less than 6.01 ounces)

Calculation the value from standard normal z table, we have,  

0.3605 is the probability  that the mean weight of the sample is less than 6.01 ounces.

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step-by-step explanation:

9 x 8 divided by (5-3)=36