) Suppose that an urn contains 7 green, 8 red, and 9 yellow balls. You pick a ball at random and replace it. You then do this 9 more times (making 10 times altogether). What is the probability that you selected green 2 times, red 3 times, and yellow 5 times?

Title:

Step-by-step explanation:

In the urn, there are total (7 + 8 + 9) = 24 balls.

We are taking 10 balls out of the urn with replacement.

In each tern, we have overall 10 choices to chose 1 ball.

If we want to get a green, there are 7 choices each time.

Similarly, 8 choices each time for getting a red and 9 choices each time for getting a yellow ball.

The probability of getting green 2 times, red 3 times, and yellow 5 times is .

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

5 pm

step-by-step explanation: