Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of success of 0.55 and enter the answers below. Round the mean to the nearest integer and the standard deviation to two decimal places.

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

where, n = number of trials (samples) taken = 680 trials

            r = number of success  

           p = probability of success which in our question is 0.55

So, it means X ~

Now, we have to find the mean and standard deviation of the given binomial distribution.

                    E(X) = n p

       So, E(X) = 680 0.55 = 374

                   S.D.(X) =

                               =

                               = = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

what is the original number? you forgot to add it.

whose power in the senate is equal to the power of the speaker of the house?

step-by-step explanation: