A wrench 0.1 meters long lies along the positive yy-axis, and grips a bolt at the origin. A force is applied in the direction of ⟨0,2,−4⟩⟨0,2,−4⟩ at the end of the wrench. Find the magnitude of the force in Newtons needed to supply 100 Newton-Meters of torque to the bolt.

Therefore the magnitude of the applied force is N.

Step-by-step explanation:

Torque: Torque is the cross product of force and the distance of applied force  from the rotational axis.

Where is angle between F and r.

Newton-meter is the S.I unit of torque.

Along the positive y axis, the wrench lies .

The length of wrench is 0.1 m.

  [ since the vector lies on y axis]

The direction of applied force is along the vector <0,2,-4>.

Then the angle between and <0,2,-4> = the angle between F and .

We know that,

We know that,

Here = 100 N-m, and

Now

Therefore the magnitude of the force is N.

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

idk

step-by-step explanation:

use that smart brain