Find an equation for the nth term of a geometric sequence where the second and fifth terms are -8 and 512

= 2

Step-by-step explanation:

The n th term of a geometric sequence is

= a

where a is the first term and r the common ratio

Given

= - 8, then ar = - 8 → (1)

Given

= 512, then a = 512 → (2)

Divide (2) by (1)

= , thus

r³ =- 64 ( take the cube root of both sides )

r = = - 4

Substitute r = - 4 into (1)

a(- 4) = - 8

- 4a = - 8 ( divide both sides by - 4 )

a = 2

Thus

= 2

hey! so 1 (25) out of 4 (100) is 25 so your answer is 25%. it's like quarters!

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180