ACCORDING TO THE FEBRUARY 2008 FEDERAL trade commission reports on consumer fraud and identity theft, Alaska had 321 complaints of identity theft out of 1,432 consumer complaints. Calculate 90% confidence interval

 (0.205905, 0.242095)

Step-by-step explanation:

We know that the confidence interval for population proportion is given by :-

, where = sample proportion

n= sample size

Let p be the proportion of complaints of identity theft .

As per given , we have

n= 1432

By standard normal table , z* = 1.645 for 90% confidence level.

Now , 90% confidence interval for p will be :

Hence, required confidence interval = (0.205905, 0.242095)

goog may have it for you

what statement? is there an image?