Let A = {1, 2, 3, 4, 5, 6}, and consider the following equivalence relation R on A: R = {(1, 1),(2, 2),(3, 3),(4, 4),(5, 5),(6, 6),(2, 3),(3, 2),(4, 5),(5, 4),(4, 6),(6, 4),(5, 6),(6, 5)}. Show the partition of A defined by the equivalence classes of R.

A = C₁ U C₂ U C₄ = ,

C₁ = 'class of one' =  {1}

C₂ = 'class of two' =  {2,3}

C₄ = 'class of four' = {4,5,6}

Step-by-step explanation:

We need to find the equivalence classes of A. Since 1 does only relates to itself, then the class of 1 only has 1 element, which is 1 itself.

2, apart from itself, only does relate with 3. Thus, the equivalence class of 2 contains 2 elements: 2 and 3 (note that 3 also relates only with 2 apart fromm itself.

The remaining 3 elements, 4, 5 and 6 relate between each other, thus, they form an entire equivalence class, the equivalence class of 4.

Those are the equivalence classes of A.

10 - 75

step-by-step explanation:

there's nothing attached so it's most likely anything in that range.

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right