![A)\ \ \ \ \left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]](/tpl/images/0571/2778/7b34b.png)
![\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right]](/tpl/images/0571/2778/46618.png)
, it's inverse is calculated using the formula:![\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]^{-1}=\frac{1}{det\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] }\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]](/tpl/images/0571/2778/f4dea.png)
![\frac{1}{det\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right] }\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right] \\\\\\\\\#det\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right] =1\\\\\\\\=\frac{1}{1}\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right] \\\\\\\\=\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]](/tpl/images/0571/2778/75304.png)
![\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]](/tpl/images/0571/2778/d7b2e.png)
Consider the matrix shown below:
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