Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 8 feet and a height of 8 feet. Container B has a diameter of 6 feet and a height of 13 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. To the nearest tenth, what is the percent of Container A that is empty after the pumping is complete?

91.4%

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

Considering cylinder A,

Height = 8ft

Diameter = 8 ft

Radius = diameter/2 = 8/2 = 4ft

Therefore,

Volume = 3.14 × 4² × 8 = 401.92ft³

Considering cylinder B,

Height = 13ft

Diameter = 6 ft

Radius = diameter/2 = 6/2 = 3ft

Therefore,

Volume = 3.14 × 3² × 13 = 367.38ft³

The volume of Container A that would be left empty after container B is pumped into it is

367.38ft³

the percent of Container A that is empty after the pumping is complete is

367.38/401.92 × 100 = 91.4%

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x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)