A marketing research company desires to know the mean consumption of meat per week among people over age 3131. A sample of 369369 people over age 3131 was drawn and the mean meat consumption was 2.42.4 pounds. Assume that the population standard deviation is known to be 0.70.7 pounds. Construct the 85%85% confidence interval for the mean consumption of meat among people over age 3131. Round your answers to one decimal place.

The 85% confidence interval for the mean consumption of meat among people over age 31 is between 2.3 and 2.5 pounds

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 2.4 - 0.1 = 2.3 pounds

The upper end of the interval is the sample mean added to M. So it is 2.4 + 0.1 =  2.5 pounds

The 85% confidence interval for the mean consumption of meat among people over age 31 is between 2.3 and 2.5 pounds

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.

180°

step-by-step explanation:

sum of equilateral triangle=180°

< n=60°

< m=120°°[angle supplementary of equilateral angle]

< m+< r+< x=360°(sum of exterior angle of triangle)