About how many times more intense is an earthquake that measures 8.2 on the Richter scale than an earthquake that measures 7.3 on the Richter scale? Recall that Richter defined the magnitude R of an earthquake of intensity I to be
R = log I. (Round your answer to two decimal places.)

About 7.94 times

Step-by-step explanation:

The intensity of an earthquake can be found using the formula:

Where

I is the intensity

I_0 is intensity of magnitude 0 earthquake

M is Richter scale magnitude

For first quake, it will be:

For the second quake, it will be:

The times the intensity is more can be found by dividing both, so we have:

The first earthquake is about 7.94 times the second quake

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho