A water rocket is projected vertically upward from the ground. Its a height(h) m above the ground after t seconds is given by h=20-5(t-2)^2. When will the rocket reach the ground?
MARKING THE BRAINLIEST

The rocket will reach the ground 4seconds after.

Given the height reached by the rocket expressed as shown;

The rocket will reach the ground when h(t) = 0

Substitute h(t) = 0 into the expression as shown:

Expand the expression:

This means that the rocket will reach the ground 4seconds after.

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after 4 seconds

Step-by-step explanation:

Given

h = 20 - 5(t - 2)²

When rocket is on ground then h = 0

Equate to zero and solve for t

20 - 5(t - 2)² = 0 ( subtract 20 from both sides )

- 5(t - 2)² = - 20 ( divide both sides by - 5 )

(t - 2)² = 4 ( take the square root of both sides )

t - 2 = ± = ± 2 ( add 2 to both sides )

t = 2 ± 2

Thus

t = 2 - 2 = 0 ← when rocket is launched

t = 2 + 2 = 4 ← when rocket hits the ground

The rocket reaches the ground after 4 seconds

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic