What is the radius of the circle x2 + y2 -1=0?

1

Step-by-step explanation:

rewrite x^2 + y^2 -1 = 0 as x^2 + y^2 = 1

the 1 on the right hand side of the equation is equal to the radius squared

1 = r^2

r = 1

radius = 1

Step-by-step explanation:

x^2 + y^2 -1=0

Add 1 to each side

x^2 + y^2 -1+1=0+1

x^2+y^2 = 1

This is written in the form

(x-h)^2 + (y-k)^2 = 1^2  where (h,k) is the center and r is the radius

The center is (0,0) and the radius is 1

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).