Find four consecutive even integers such that if the sum of the first and third is multiplied by 3, the result is 28 less than five times the fourth

Step-by-step explanation:

We can solve the problem in this way:

- The 1st information that we have is that the four numbers are even and consecutive integer. Let's call these numbers A, B, C and D. This means that:

(since the distance between two even consecutive numbers is 2)

- The 2nd information that is given is that the sum of the first and third multiplied by 3 equals 28 less than 5 times the fourth, so:

(1)

Now we rewrite eq(1) by using:

and

(obtained by combining the 3 first equations)

So we get:

Solving this equation for C,

So the other numbers are:

3201

step-by-step explanation: