Write an equation in slope-intercept form of the line with the given parametric equations.
x = -3t+5
y = 8t+9

y =

Step-by-step explanation:

to do this, write t in terms of x, then substitute t in y

Write t in terms of x

x = -3t + 5

x - 5 = -3t

t = -x/3 + 5/3

Substitute t in y

t = -x/3 + 5/3

y = 8t + 9

y = 8(-x/3 + 5/3) + 9

y = -8x/3 + 40/3 + 9

y = -8x/3 + 40/3 + 27/3

y = -8x/3 + 67/3

y =

y = (-8/3)x + 67/3

Step-by-step explanation:

x = -3t + 5

t = (5 - x)/3

y = 8t + 9

y = 8(5 - x)/3 + 9

y = 40/3 - 8x/3 + 9

y = -8x/3 + 67/3

y = (-8/3)x + 67/3

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: