H(x)=1/8x^3-x^2 what is the average rate of change of h over the interval -2

the average rate of change of h is 1/2 .

Step-by-step explanation:

Here we have , a function h(x)=1/8x^3-x^2 or , . We need to find rate of change of function over . Let's find out:

We know that , Rate of change of function is :

According to question we have ,

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⇒

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Therefore ,  the average rate of change of h is 1/2 .

look a the sides they are perpendicular

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: