Alabrador leaps over a hurdle. the function f(t) represents the height of the labrador above the ground, in inches, at t seconds: . f(t) = -16t^2 + 26t . a foxhound jumps over the same hurdle. the table shows the height of the foxhound above the ground g(t), in inches, at t seconds: . time: g(t): . 0 0 . 0.4 6.24 . 0.6 7.44 . 0.7 7.56 . 0.8 7.36 . 1.0 6 . 1.4 0 .

Part a) the max of g(t) occurs when t=0.6 seconds, for f(t) since the parabola is concave down due to the negative sign then we know that there is a max on the parabola, the max for f(t) occurs at (13/16,169/16) 169/6=10.5625inches at time 0.8125seconds Part b) f(t) has greater x intercepts, meaning that when the labrador will land later than the fox when it jumps over the hurdle

The answer is 6 weeks