Algebra 2 Please help
11 points + A thanks

Step-by-step explanation:

7a - The perimeter of the fence is the sum of the whole path around the fence (2 * length + 2 * width). In this question, L = x+4, and w = 2x - 23 so the perimeter is

2L + 2w

= 2(x+4) + 2(2x-23) distribute the terms through the parentheses

= 2x + 8 + 4x - 46 combine like terms

= 6x - 38

7b - The area is equal to length * width

L * w

= (x+4) * (2x-23) foil the terms

= (x * 2x) + (x * -23) + (4 * 2x) + (4 * -23)

= 2x^2 - 23x + 8x - 92 combine like terms

= 2x^2 - 15x - 92

7c - The equation for the perimeter in part a is 6x - 38, and it is given in part c that the fence is 76 feet, so solve for x

6x - 38 = 76 set equations equal to each other

6x = 114

x = 19

now that we know x, we can plug x into the length and width equations that were given

length = x + 4 = 19 + 4 = 23

width = 2x - 23 = 2 * 19 - 23 = 38 - 23 = 15

so length = 23 feet and width = 15 feet

7d - In part b we created an equation for area, and in part c we figured out the value of x. so to find the area, plug x into the equation from part c

area = 2x^2 - 15x - 92

x = 19

area = 2*(19)^2 - (15* 19) - 92 = 722 - 285 - 92 = 345

so area = 345 feet^2

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

step-by-step explanation:

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