Box A can hold 10 marbles. Box B is double the height of Box A, four times the length of Box A, and half the width of box A. How many marbles can Box B hold?

40 marbles.

Step-by-step explanation:

Given:

Box A can hold 10 marbles.

Box B is double the height of Box A, four times the length of Box A, and half the width of box A.

Question asked:

How many marbles can Box B hold?

Solution:

Let volume of box A =

Let volume of box B =

Now, suppose:

Length of box A =

Breadth =

Height =

So, volume of box A,

As given, Box B is double the height of Box A, four times the length of Box A, and half the width of box A.

So, Length of box B =

     Breadth =

     Height =

Volume of box B, =

By dividing volume of box A with volume of box B:

By cross multiplication:

That means volume of box B is 4 times volume of box A;

∵ Box A can hold = 10 marbles

∴ Box B ( 4 times of box A ) can hold =

Therefore, Box B can hold 40 marbles.

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>