The difference between two positive integers is 2. If the smaller is added to the square of the larger, the sum is 130.

The two integers are 11 and 9.

Step-by-step explanation:

So i made to equations where the larger integer is x and the smaller one is y:

x-y=2

x^2+y=130

Then I added the equations, cancelling out the y. Then I was left with:

x^2+x=132

Then I used factoring to solve teh quadratic equation:

x^2+x-132=0

x^2-11x+12x-132=0

x(x-11)+12(x-11)=0

(x+12)(x-11)=0

So, x is equal to -12 or 11.

The question says that the numbers are positive so it cannot be -12.

Therefore,  is equal to 11, and when you plug it back in, y is 9.

I hope this was helpful!!

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )